Data interpretation Solved questions for competitive exams:Line Graph

Data Interpretation Question and Answers: Line Graph

1. The following line-graph gives the ratio of the amounts of imports by a Company to the amount of exports from that Company over the period from 1995 to 2001. The questions given below are based on this graph. (S.B.I.P.0. 2001)

1. In how many of the given years were the exports more than the imports ?

a)      1

b)      2

c)       3

d)      4

e)      None of these

2. The imports were minimum proportionate to the exports of the Company in the year

a)      1995

b)      1996

c)       1997

d)      2000

e)      2001

3. If the imports of the Company in 1996 was Rs. 272 crores, the exports from the Company in 1996 was:

a)      Rs. 370 crores

b)      Rs. 320 crores

c)       Ra. 280 crores

d)      Rs. 275 crores

e)      Rs. 264 crores

4.What was the percentage increase in imports from 1907 to 1998?

a)      72

b)      56

c)       28

d)      None of these

e)      Data inadequate

5. If the imports in 1998 was Rs. 250 crores and the total exports in the years 1998 and

1999 together was Rs. 500 crores, then the imports in 1999 was

a)      Rs. 250 crores

b)      Rs. 300 crores

c)       Rs. 357 crores

d)      Rs. 420 crores

e)      None of these

Sol. 1. (d): The exports are more than the imports implies that the ratio of value of imports to exports is less than 1.

Now, this ratio is less than 1 in the years 1995, 1996, 1997 and 2000.

Thus, there are four such years.

2. (c) The imports are minimum proportionate to the exports implies that the ratio of the value of imports to exports has the minimum value.

Now, this ratio has a minimum value of 0.35 in 1997, i.e., the imports are minimum proportionate to the exports in 1997.

 3. (b) Ratio of imports to exports in the year 1996 = 0.85.

Let the exports in 1996 = Rs. x crores

Then, 272/x = 0.85 =>  x= 272/0.85= 320

Exports in 1996 = Rs. 320 crores.

 4. (e)The graph gives only the ratio of imports to exports for different years. To find the percentage increase in imports from 1997 to 1998, we require more details such as the value of imports or exports during these years. Hence, the data is inadequate to answer this question.

5.(d)The ratio of imports to exports for the years 1998 and 1999 are 1.25 and 1.40 respectively.

Let the exports in the year 1998 = Rs. x crores.

Then, the exports in the year 1999 Rs. (500-x ) crores.

Therefore 1.25= 250/x => x=250/1.25 =200                   [Using ratio for 1998]

Thus, the exports in the year 1999 =Rs. (500 -200) crores = Rs. 300 crores.

Let the imports in the year 1999=  Rs. y crores.

 Then, 1.40 = y /300 => y= (300 x 1.40) = 420.

Therefore, Imports  in the year 1999 = Rs. 420 crores.

 

3. Study the following line-graph and answer the questions based on it.(R.B.I. 2003)

1 What is the difference between the total productions of the two Companies in the given years ?

a)      19000

b)      22000

c)       26000

d)      28000

e)      29000

2. What is the difference between the numbers of vehicles manufactured by Company Y in 2000 and 2001?

a)      50000

b)      42000

c)       33000

d)      21000

e)      13000

3. What is the average number of vehicles manufactured by Company X over the given period? (rounded off to the nearest integer)

a)      119333

b)      113666

c)       112778

d)      111223

e)      None of these

4. In which of the following years, the difference between the productions of Companies X and Y was the maximum among the given years ?

a)      1997

b)      1998

c)       1999

d)      2000

e)      2001

5. The production of Company Y in 2000 was approximately what percent of the production of Company X in the same year?

a)      173

b)      164

c)       132

d)      97

e)      61

Sol. From the line-graph it is clear that the productions of Company X in the years 1997, 1998, 1999, 2000, 2001 and 2002 are 119000, 99000, 141000, 78000, 120000 and 159000 respectively and those of Company Y are 139000, 120000, 100000, 128000, 107000 and 148000 respectively.

1. (c) Total production of Company X from 1997 to 2002 = 119000 + 99000 + 141000 + 78000 + 120000 +159000 =716000.

and total production of Company Y from 1997 to 2002 = 139000 +120000 100000+ 128000+ 107000 148000 =742000.

Difference = 742000 716000 = 26000.

 

2.(d) Required difference = 128000- 107000 =21000.

 

3. (a) Average number of vehicles manufactured by Company X=1/6 X (119000+ 99000 + 141000+ 78000+ 120000+ 159000) =119333.

 

4. (a) The difference between the years are productions of Companies X and Y in various years are

For 1997 = (139000 119000) = 20000.

For 1998 (120000 99000) = 21000.

For 1999 = (141000 100000)= 41000

For 2000 = (128000 - 78000) = 50000

For 2001 (120000 -107000) = 13000

For 2002 = (159000 148000) = 11000.

Clearly, maximum difference was in 2000

 

5.(b) Required percentage= [(128000/78000)× 100 ]% =164%

 

3. The following line-graph gives the percent profit earned by two Companies X and Y during the period 1996 2001. Study the line-graph and answer the questions based on it. (NABARD, 2002)

 % profit/Loss  =[(Income-Expenditure)/Expenditure]×100

1. If the expenditure of Company Y in 1997 was Rs. 220 crores, what was its income in 1997.?

a)      Rs. 312 crores

b)      Rs. 297 crores

c)       Rs. 283 crores

d)      Rs 275 crores

e)      Rs. 261 crores

2. If the incomes of the two Companies were equal in 1999, then what was the ratio of expenditure of Company X to that of Company Y in 1999 ?

a)      6:5

b)      5:6

c)       11:6

d)      16:15

e)      15:16

3. The incomes of the Companies X and Y in 2000 were in the ratio of 3:4 .What was the ratio of their expenditure in 2000 ?

a)      7:22

b)      14:19

c)       15:22

d)      27:35

e)      33:40

4.If the expenditures of Companies X and Yin 1996 were equal and the total income of the two companies in 1996 was Rs. 342 crores, what was the total profit of the two Companies together in 1996? (Profit = Income - Expenditure)

a)      Rs. 240 crores

b)      Rs. 171 crores

c)       Rs. 120 crores

d)      Rs. 102 crores

e)      None of these

5. The expenditure of Company X in the year 1998 was Rs. 200 crores and the income of Company X in 1998 was the same as its expenditure in 2001. The income of Company X in 2001 was

a)      Rs. 465 crores

b)      Rs. 385 crores

c)       Rs. 335 crores

d)      Rs. 295 crores

e)      Rs. 255 crores

 

Sol. 1. (b) Profit percent of Company Y in 1997=35.

Let the income of Company Y in 1997 be Rs. x crores.

Then,  35= [(x-220)/220]×100 => x=297

Therefore income of Company Y in 1997=Rs.297 crores.

2. (d)Let the incomes of each of the two Companies X and Y in 1999 be Rs. X. And let the expenditures of Companies X and Y in 1999 be E₁ and E₂  respectively.

Then,for Company X we have :

50= [(x- E₁)/ E₁] ×100  => x= (150/100) E₁

Also for Company Y we have

60= [(x- E₂)/ E₂] ×100  => x= (160/100) E₂

 From above two results

(150/100) E₁ = (160/100) E₂

E₁/ E₂ = 160/150 =16/15 [Required ratio]

 

3.(c) Let the incomes in 2000 of Companies X and Y be 3x and 4x respectively. And let the expenditures in 2000 of Companies X and Y be E₁ and E₂ respectively.

Then, for Company X we have,

65=[(3x- E₁)/ E₁]×100  => E₁ =3x × (100/165)

For company Y we have

50=[(4x- E₂)/ E₂]×100  => E₂ =4x × (100/150)

From above two results

E₁ / E₂  = [3x × (100/165)] / [4x × (100/150)]

E₁ / E₂   = 15/22   [required ratio]

 

4. (d) Let the expenditures of, each of the Companies X and Y in 1996 be Rs. x crores .And let the income of Company X in}1996 be Rs.z crores so that the income of Company Y in 1996= Rs. (342 -z) crores. Then, for Company X we have

40= [(z-x)/x]×100 =>40/100 =(z/x) – 1  => x= (100/140)z

Also for Company Y we have

45= [((342-z)-x)/x]×100 =>45/100 =((342-z)/x) – 1  => x= (100/145) ×(342-z)

 From above two results

(100/140)z = (100/145) ×(342-z)  => z=168

Substituting z in equation x= (100/140)z we get x=120.

Therefore total expenditure of Companies X and Y in 1996 =2x =Rs.240 crores

Total Income of Companies X and Y 1996 =Rs.342 crores.

Total profit = Rs.(342-240)Crores= Rs.102 crores.

 

5.(a)  Let the income of Company X in 1998 be Rs.x crores.

Then,55= [(x-200)/200 ] ×100

ð  x=310

Therefore expenditure of Company X in 2001 = Income of Company X in 1998 =Rs.310 crores

Let the income of Company  X in 2001 be Rs.z crores.

The ,50=[(z-310)/310] ×100

ð  z=465

Therefore income of Company X in 2001 =Rs.465 crores

Data interpretation Questions and Answers:Tabulation

 Data interpretation questions for competitive exams ,IBPS,BANK,SSC,NTPC,RRB exams:

Data interpretation questions dominates quantitative section of most of the competitive exams like, IBPS,SBI,Insurance exams,RRB,NTPC etc. It just require little practice to score well in this section.Here you can find tabular data interpretation questions and solutions. 

1.The following table gives the sales of batteries manufacture d by a company over the year. Study the table and answer the questions that follows.  (SBI PO 1998)

 Number of different types of batteries sold by a company over the year (In thousands)

Year	Types of batteries
	4AH	7AH	32AH	35AH	55AH	TOTAL
1992	75	144	114	102	108	543
1993	90	126	102	84	126	528
1994	96	114	75	105	135	525
1995	105	90	150	90	75	510
1996	90	75	135	75	90	465
1997	105	60	165	45	120	495
1998	115	85	160	100	145	605

 1.       The total sales of all the seven years is the maximum for which battery?

a)      4AH

b)      7AH       

c)       32AH                    

d)      35AH    

e)      55AH

2.       .What is the difference in the number of 35Ah batteries sold in 1993 and 1997?

a)      24000

b)      28000

c)       35000

d)      39000

e)      42000

3.       .The percentage of 4AH batteries sold to the total number of batteries sold was maximum in the year.

a)      1994

b)      1995

c)       1996

d)      1997

e)      1998

4.      . In the case of which battery there was continuous decrease in sales from 1992 to 1997?

a)      4AH

b)      7AH

c)       32AH

d)      35AH

e)      55AH

5.       .What was the approximate percentage increase in the sales of 55AH batteries in 1998 compared to   that in 1992?

a)      28%

b)      31%

c)       33%

d)      34%

e)      37%

Sol. 1. (c) The total sales (in thousands) of all the seven years for various batteries are:

For 4AH =75+90+96+105+90+105+115=676

For 7AH=144+126+114+90+75+60+85=694

For 32AH=114+102+75+150+135+165+160=901

For 35AH=102+84+105+90+75+45+100=601

For 55AH=108+126+135+75+90+120+145=799

Clearly sales are maximum in case of 32AH batteries.

2.(d): Required difference=[(84-45)×1000]=39000

3.(d): The percentage of sales of 4AH batteries to the total sales in different years are:

For 1992= [(75/543 )×100 ]%=13.81%

For 1993= [(90/528 )×100 ]%=17.05%

For 1994= [(96/525 )×100 ]%=18.29%

For 1995= [(105/510 )×100 ]%=20.59%

For 1996= [(96/465 )×100 ]%=19.35%

For 1997= [(105/495 )×100 ]%=21.21%

For 1998= [(115/605 )×100 ]%=19.01%

 Percentage is maximum in 1997

4.(b) From table it is clear that the sales of 7AH batteries decreased continuously from 1992 to 1997.

5.(d):Required percentage={ [(145-108)/100 ]×100}%=34.26%

 

2.Study the following table carefully and answer these questions (S.B.I.P.0. 2002)

NUMBER OF CANDIDATES APPEARED AND QUALIFIED IN A COMPETITIVE EXAMINATION FROM DIFFERENT STATES OVER THE YEARS

Year   State	1997		1998		1999		2000		2001
	App.	Qual.	App.	Qual.	App.	Qual.	App.	Qual.	App.	Qual.
M	5200	720	8500	980	7400	850	6800	775	9500	1125
N	7500	840	9200	1050	8450	920	9200	980	8800	1020
P	6400	780	8800	1020	7800	890	8750	1010	9750	1250
Q	8100	950	9500	1240	8700	980	9700	1200	8950	995
R	7800	870	7600	940	9800	1350	7600	945	7990	885

 

1. Combining the states P and Q together in 1998, what is the percentage of the candidates

qualified to that of the candidates appeared?

(a) 10.87% 

(b) 11.49%

(c) 12.35%

(d) 12.54%

(e)13.05%

 

2. The percentage of the total number of qualified candidates to the total number of

appeared candidates among all the five states in 1999 is

(a) 11.49%

(b) 11.84%

(c)12.21%

(d)12.57%

(e)12.73

 

3.What is the percentage of candidates qualified from State N for all the years together

over the candidates appeared from State N during all the years together ?

(a) 12.36%

(b) 12.16%

(c) 11.47%

(d) 11.15%

(e) None of these

 

4. What is the average of candidates who appeared from State Q during the given years?

(a) 8700

(b) 8760

(c) 88100

(d) 8920

(e) 8990

 

5.In which of the given years the number of candidates appeared from State P has maximum percentage of qualified candidates ?

(a) 1997

(b) 1998

(c) 1999

(d) 2000

(e) 2001

 

6.Total number of candidates qualified from all the states together in 1997 is approximately what percentage of the total number of candidates qualified from all the states together in 1998?

(a) 72%

(b) 77%

(c) 80%

(d) 83%

(e) 86%

 

Sol. 1. (c) Required Percentage [(1020 +1240) /(8800+ 9500) ]x 100 %

(8800 9500) 18300

= 12.35%

 

2. (b) Required Percentage[ (850+920 +890 +980+1350)/ (7400 + 8450 + 7800+8700 + 9800)]x100 % = 11.84%.

 

3. (d) . Required Percentage  [(840+1050+920+980+ 1020)/ (7500 + 9200 + 8450 9200 + 8800)

] x100 %= 11.15%.

 

4. (e) Required average =[(8100+9500 + 8700+9700+8950)/5]= 8990.

 

5. (e) The percentages of candidates qualified to candidates appeared from State P during different years are

 

For 1997 =[(780/6400)]×100% = 12.19%.

 

For 1998 =[(1020/8800)]×100% = 11.59%.

 

For 1999 =[(890/7800)]×100% = 11.41%.

 

For 2000 =[(1010/8750)]×100% = 11.54%.

 

For 2001= [(1250/9750)]×100% = 12.82%.

 

Maximum percentage is for the year 2001

 

6.       (c) Required Percentage =[ (720+840+ 780+950+870)/(980+1050 + 1020 + 1240+ 940)] x 100 %= 79.54% (Appx.80%)

4. Study the following table carefully and answer the questions given below

(Bank PO. 2001)

Classification of 100 students based on the marks obtained by them in Physics and Chemistry in an examination. 

Marks out of 50          Subject	40 and above	30 and above	20 and above	10 and above	0 and above
Physics	9	32	80	92	100
Chemistry	4	21	66	81	100
Average(Aggregate)	7	27	73	87	100

 1. The number of students scoring less than 40% marks in aggregate is

(a) 13

 (b) 19

(c) 20

(d) 27

(e) 34

2. If at least 60% marks in Physics are required for pursuing higher studies in Physics, how many students will be eligible to pursue higher studies in Physics

(a) 27

(b) 32

(c) 34

(d 41

(e) 68

3. What is the difference between the number of students passed with 30 as cut-off marks in Chemistry and those passed with 30 as cut-off marks in aggregate

(a )3

(b) 4

(c) 5

(d) 6

(e)7

4. The percentage of the number of students getting at least 60% marks in Chemistry over those getting at least 40% marks in aggregate, is approximately:

(a) 21%

(b) 27%

(c) 29%

(d) 31%

(e) 34%

 5. If it is known that at least 23 students were eligible for a Symposium on Chemistry, the minimum qualifying marks in Chemistry for eligibility to Symposium would lie in the range

(a) 40-50

(b) 30-40

(c) 20-300

(d) Below 20

(e) Cannot be determined

 

1. (d) We have 40% of 50 = (40/100)×50=20

Required number = Number of students scoring less than 20 marks in aggregate.

= 100 -  number of students scoring 20 and above marks in aggregate = 100 - 73 = 27.

 2. (b): We have 60% of 50 =(60/100)X 50 = 30

Required number = Number of students scoring 30 and above marks in Physics = 32.

3. (d) Required difference = (Number of students scoring 30 and above marks in Chemistry) - (Number of students scoring 30 and above marks in aggregate)= 27 -21 = 6.

4. (c) Number of students getting at least 60% marks in Chemistry = Number of students getting 30 and above marks in Chemistry = 21.

Number of students getting at least 40% marks in aggregate = Number of students getting 20 and above marks in aggregate = 73.

Required Percentage =(21/73) x 100 %= 28.77% (Appx. 29%.)

5. (c)Since 66 students get 20 and above marks in Chemistry and out of these 21 students get 30 and above marks, therefore to select top 35 students in Chemistry, the qualifying marks should lie in the range 20-30.